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0.8x^2-16x+60=0
a = 0.8; b = -16; c = +60;
Δ = b2-4ac
Δ = -162-4·0.8·60
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{64}=8$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-8}{2*0.8}=\frac{8}{1.6} =5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+8}{2*0.8}=\frac{24}{1.6} =15 $
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